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    Coupling selection case calculation

    2022-02-13|admin


    There are usually two ways to choose a coupling:


    Select a suitable coupling according to the maximum torque, i.e. the peak torque required by the load should not exceed the rated torque of the coupling:


    TKN ≧ 1.5 TAS Nm


    The coupling is selected according to the acceleration torque. At this time, the rotational inertia of the drive system needs to be considered. If the inertia ratio is large, the influence of the load factor in the calculation of the coupling specification will be reduced:


    聯(lián)軸器負(fù)載系數(shù)計(jì)算.png

    振動(dòng)或負(fù)載系數(shù) SA

    均勻載荷

    非均勻載荷

    高動(dòng)態(tài)載荷

    1

    2

    3-4

    對(duì)伺服電機(jī)來說,負(fù)載系數(shù)通常為SA=2-3

     

    Calculation example:


    Servo motor drive, maximum torque TAS=50Nm


    Load factor SA=3


    聯(lián)軸器選型計(jì)算.png

    So 聯(lián)軸器選型計(jì)算公式.pngIt can be seen that when the load inertia is relatively large, the inertia of the coupling itself has little influence on the calculation results.


    In addition to the torque, it is necessary to consider whether the speed meets the requirements. Most of the R+W couplings have been preliminarily balanced before leaving the factory. The default speed of some smaller models can reach 10000rpm. If the equipment needs The rotation speed is relatively high, and additional dynamic balancing treatment is required.


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